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0=3x^2+10x+125
We move all terms to the left:
0-(3x^2+10x+125)=0
We add all the numbers together, and all the variables
-(3x^2+10x+125)=0
We get rid of parentheses
-3x^2-10x-125=0
a = -3; b = -10; c = -125;
Δ = b2-4ac
Δ = -102-4·(-3)·(-125)
Δ = -1400
Delta is less than zero, so there is no solution for the equation
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